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2n^2+18n-104=0
a = 2; b = 18; c = -104;
Δ = b2-4ac
Δ = 182-4·2·(-104)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-34}{2*2}=\frac{-52}{4} =-13 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+34}{2*2}=\frac{16}{4} =4 $
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